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Konfidenzintervalle
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@ -109,6 +109,20 @@ mithilfe einer konkreten Stichprobe $(x_1, \ldots, x_n)$.
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\item Ableiten nach $\lambda$: $\frac{\partial \ln * L(\lambda)}{\partial \lambda}$
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\item Funktion gleich $0$ setzen und nach $\lambda$ aufloesen.
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\end{enumerate}
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\subsection{Konfidenzintervalle}
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Standartwerte fuer Konfidenz:
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\begin{align*}
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90\%:z = 1.65\\
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95\%:z = 1.96\\
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99\%:z = 2.58
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\end{align*}
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\begin{align}
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P(|\bar{x}-\mu| \geq c) = \alpha \\
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\mu \in [\bar{x} - z_{1-\frac{\alpha}{2}} * \frac{\sigma}{\sqrt{n}}]
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\end{align}
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\section{Mengen}
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\subsection{o-Algebra}
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- leere Menge enthalten\\
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