anki/tests/test_schedv2.py

1152 lines
30 KiB
Python

# coding: utf-8
import time
import copy
from anki.consts import STARTING_FACTOR
from tests.shared import getEmptyCol as _getEmptyCol
from anki.utils import intTime
from anki.hooks import addHook
def getEmptyCol():
return _getEmptyCol(schedVer=2)
def test_clock():
d = getEmptyCol()
if (d.sched.dayCutoff - intTime()) < 10*60:
raise Exception("Unit tests will fail around the day rollover.")
def checkRevIvl(d, c, targetIvl):
min, max = d.sched._fuzzIvlRange(targetIvl)
return min <= c.ivl <= max
def test_basics():
d = getEmptyCol()
d.reset()
assert not d.sched.getCard()
def test_new():
d = getEmptyCol()
d.reset()
assert d.sched.newCount == 0
# add a note
f = d.newNote()
f['Front'] = "one"; f['Back'] = "two"
d.addNote(f)
d.reset()
assert d.sched.newCount == 1
# fetch it
c = d.sched.getCard()
assert c
assert c.queue == 0
assert c.type == 0
# if we answer it, it should become a learn card
t = intTime()
d.sched.answerCard(c, 1)
assert c.queue == 1
assert c.type == 1
assert c.due >= t
# disabled for now, as the learn fudging makes this randomly fail
# # the default order should ensure siblings are not seen together, and
# # should show all cards
# m = d.models.current(); mm = d.models
# t = mm.newTemplate("Reverse")
# t['qfmt'] = "{{Back}}"
# t['afmt'] = "{{Front}}"
# mm.addTemplate(m, t)
# mm.save(m)
# f = d.newNote()
# f['Front'] = u"2"; f['Back'] = u"2"
# d.addNote(f)
# f = d.newNote()
# f['Front'] = u"3"; f['Back'] = u"3"
# d.addNote(f)
# d.reset()
# qs = ("2", "3", "2", "3")
# for n in range(4):
# c = d.sched.getCard()
# assert qs[n] in c.q()
# d.sched.answerCard(c, 2)
def test_newLimits():
d = getEmptyCol()
# add some notes
g2 = d.decks.id("Default::foo")
for i in range(30):
f = d.newNote()
f['Front'] = str(i)
if i > 4:
f.model()['did'] = g2
d.addNote(f)
# give the child deck a different configuration
c2 = d.decks.confId("new conf")
d.decks.setConf(d.decks.get(g2), c2)
d.reset()
# both confs have defaulted to a limit of 20
assert d.sched.newCount == 20
# first card we get comes from parent
c = d.sched.getCard()
assert c.did == 1
# limit the parent to 10 cards, meaning we get 10 in total
conf1 = d.decks.confForDid(1)
conf1['new']['perDay'] = 10
d.reset()
assert d.sched.newCount == 10
# if we limit child to 4, we should get 9
conf2 = d.decks.confForDid(g2)
conf2['new']['perDay'] = 4
d.reset()
assert d.sched.newCount == 9
def test_newBoxes():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
d.reset()
c = d.sched.getCard()
d.sched._cardConf(c)['new']['delays'] = [1,2,3,4,5]
d.sched.answerCard(c, 2)
# should handle gracefully
d.sched._cardConf(c)['new']['delays'] = [1]
d.sched.answerCard(c, 2)
def test_learn():
d = getEmptyCol()
# add a note
f = d.newNote()
f['Front'] = "one"; f['Back'] = "two"
f = d.addNote(f)
# set as a learn card and rebuild queues
d.db.execute("update cards set queue=0, type=0")
d.reset()
# sched.getCard should return it, since it's due in the past
c = d.sched.getCard()
assert c
d.sched._cardConf(c)['new']['delays'] = [0.5, 3, 10]
# fail it
d.sched.answerCard(c, 1)
# it should have three reps left to graduation
assert c.left%1000 == 3
assert c.left//1000 == 3
# it should by due in 30 seconds
t = round(c.due - time.time())
assert t >= 25 and t <= 40
# pass it once
d.sched.answerCard(c, 3)
# it should by due in 3 minutes
dueIn = c.due - time.time()
assert 179 <= dueIn <= 180*1.25
assert c.left%1000 == 2
assert c.left//1000 == 2
# check log is accurate
log = d.db.first("select * from revlog order by id desc")
assert log[3] == 3
assert log[4] == -180
assert log[5] == -30
# pass again
d.sched.answerCard(c, 3)
# it should by due in 10 minutes
dueIn = c.due - time.time()
assert 599 <= dueIn <= 600*1.25
assert c.left%1000 == 1
assert c.left//1000 == 1
# the next pass should graduate the card
assert c.queue == 1
assert c.type == 1
d.sched.answerCard(c, 3)
assert c.queue == 2
assert c.type == 2
# should be due tomorrow, with an interval of 1
assert c.due == d.sched.today+1
assert c.ivl == 1
# or normal removal
c.type = 0
c.queue = 1
d.sched.answerCard(c, 4)
assert c.type == 2
assert c.queue == 2
assert checkRevIvl(d, c, 4)
# revlog should have been updated each time
assert d.db.scalar("select count() from revlog where type = 0") == 5
def test_relearn():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
c = f.cards()[0]
c.ivl = 100
c.due = d.sched.today
c.type = c.queue = 2
c.flush()
# fail the card
d.reset()
c = d.sched.getCard()
d.sched.answerCard(c, 1)
assert c.queue == 1
assert c.type == 3
assert c.ivl == 1
# immediately graduate it
d.sched.answerCard(c, 4)
assert c.queue == c.type == 2
assert c.ivl == 1
assert c.due == d.sched.today + c.ivl
def test_relearn_no_steps():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
c = f.cards()[0]
c.ivl = 100
c.due = d.sched.today
c.type = c.queue = 2
c.flush()
conf = d.decks.confForDid(1)
conf['lapse']['delays'] = []
d.decks.save(conf)
# fail the card
d.reset()
c = d.sched.getCard()
d.sched.answerCard(c, 1)
assert c.type == c.queue == 2
def test_learn_collapsed():
d = getEmptyCol()
# add 2 notes
f = d.newNote()
f['Front'] = "1"
f = d.addNote(f)
f = d.newNote()
f['Front'] = "2"
f = d.addNote(f)
# set as a learn card and rebuild queues
d.db.execute("update cards set queue=0, type=0")
d.reset()
# should get '1' first
c = d.sched.getCard()
assert c.q().endswith("1")
# pass it so it's due in 10 minutes
d.sched.answerCard(c, 3)
# get the other card
c = d.sched.getCard()
assert c.q().endswith("2")
# fail it so it's due in 1 minute
d.sched.answerCard(c, 1)
# we shouldn't get the same card again
c = d.sched.getCard()
assert not c.q().endswith("2")
def test_learn_day():
d = getEmptyCol()
# add a note
f = d.newNote()
f['Front'] = "one"
f = d.addNote(f)
d.sched.reset()
c = d.sched.getCard()
d.sched._cardConf(c)['new']['delays'] = [1, 10, 1440, 2880]
# pass it
d.sched.answerCard(c, 3)
# two reps to graduate, 1 more today
assert c.left%1000 == 3
assert c.left//1000 == 1
assert d.sched.counts() == (0, 1, 0)
c = d.sched.getCard()
ni = d.sched.nextIvl
assert ni(c, 3) == 86400
# answering it will place it in queue 3
d.sched.answerCard(c, 3)
assert c.due == d.sched.today+1
assert c.queue == 3
assert not d.sched.getCard()
# for testing, move it back a day
c.due -= 1
c.flush()
d.reset()
assert d.sched.counts() == (0, 1, 0)
c = d.sched.getCard()
# nextIvl should work
assert ni(c, 3) == 86400*2
# if we fail it, it should be back in the correct queue
d.sched.answerCard(c, 1)
assert c.queue == 1
d.undo()
d.reset()
c = d.sched.getCard()
d.sched.answerCard(c, 3)
# simulate the passing of another two days
c.due -= 2
c.flush()
d.reset()
# the last pass should graduate it into a review card
assert ni(c, 3) == 86400
d.sched.answerCard(c, 3)
assert c.queue == c.type == 2
# if the lapse step is tomorrow, failing it should handle the counts
# correctly
c.due = 0
c.flush()
d.reset()
assert d.sched.counts() == (0, 0, 1)
d.sched._cardConf(c)['lapse']['delays'] = [1440]
c = d.sched.getCard()
d.sched.answerCard(c, 1)
assert c.queue == 3
assert d.sched.counts() == (0, 0, 0)
def test_reviews():
d = getEmptyCol()
# add a note
f = d.newNote()
f['Front'] = "one"; f['Back'] = "two"
d.addNote(f)
# set the card up as a review card, due 8 days ago
c = f.cards()[0]
c.type = 2
c.queue = 2
c.due = d.sched.today - 8
c.factor = STARTING_FACTOR
c.reps = 3
c.lapses = 1
c.ivl = 100
c.startTimer()
c.flush()
# save it for later use as well
cardcopy = copy.copy(c)
# try with an ease of 2
##################################################
c = copy.copy(cardcopy)
c.flush()
d.reset()
d.sched.answerCard(c, 2)
assert c.queue == 2
# the new interval should be (100) * 1.2 = 120
assert checkRevIvl(d, c, 120)
assert c.due == d.sched.today + c.ivl
# factor should have been decremented
assert c.factor == 2350
# check counters
assert c.lapses == 1
assert c.reps == 4
# ease 3
##################################################
c = copy.copy(cardcopy)
c.flush()
d.sched.answerCard(c, 3)
# the new interval should be (100 + 8/2) * 2.5 = 260
assert checkRevIvl(d, c, 260)
assert c.due == d.sched.today + c.ivl
# factor should have been left alone
assert c.factor == STARTING_FACTOR
# ease 4
##################################################
c = copy.copy(cardcopy)
c.flush()
d.sched.answerCard(c, 4)
# the new interval should be (100 + 8) * 2.5 * 1.3 = 351
assert checkRevIvl(d, c, 351)
assert c.due == d.sched.today + c.ivl
# factor should have been increased
assert c.factor == 2650
# leech handling
##################################################
c = copy.copy(cardcopy)
c.lapses = 7
c.flush()
# steup hook
hooked = []
def onLeech(card):
hooked.append(1)
addHook("leech", onLeech)
d.sched.answerCard(c, 1)
assert hooked
assert c.queue == -1
c.load()
assert c.queue == -1
def test_review_limits():
d = getEmptyCol()
parent = d.decks.get(d.decks.id("parent"))
child = d.decks.get(d.decks.id("parent::child"))
pconf = d.decks.getConf(d.decks.confId("parentConf"))
cconf = d.decks.getConf(d.decks.confId("childConf"))
pconf['rev']['perDay'] = 5
d.decks.updateConf(pconf)
d.decks.setConf(parent, pconf['id'])
cconf['rev']['perDay'] = 10
d.decks.updateConf(cconf)
d.decks.setConf(child, cconf['id'])
m = d.models.current()
m['did'] = child['id']
d.models.save(m)
# add some cards
for i in range(20):
f = d.newNote()
f['Front'] = "one"; f['Back'] = "two"
d.addNote(f)
# make them reviews
c = f.cards()[0]
c.queue = c.type = 2
c.due = 0
c.flush()
tree = d.sched.deckDueTree()
# (('Default', 1, 0, 0, 0, ()), ('parent', 1514457677462, 5, 0, 0, (('child', 1514457677463, 5, 0, 0, ()),)))
assert tree[1][2] == 5 # parent
assert tree[1][5][0][2] == 5 # child
# .counts() should match
d.decks.select(child['id'])
d.sched.reset()
assert d.sched.counts() == (0, 0, 5)
# answering a card in the child should decrement parent count
c = d.sched.getCard()
d.sched.answerCard(c, 3)
assert d.sched.counts() == (0, 0, 4)
tree = d.sched.deckDueTree()
assert tree[1][2] == 4 # parent
assert tree[1][5][0][2] == 4 # child
# switch limits
d.decks.setConf(parent, cconf['id'])
d.decks.setConf(child, pconf['id'])
d.decks.select(parent['id'])
d.sched.reset()
# child limits do not affect the parent
tree = d.sched.deckDueTree()
assert tree[1][2] == 9 # parent
assert tree[1][5][0][2] == 4 # child
def test_button_spacing():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
# 1 day ivl review card due now
c = f.cards()[0]
c.type = 2
c.queue = 2
c.due = d.sched.today
c.reps = 1
c.ivl = 1
c.startTimer()
c.flush()
d.reset()
ni = d.sched.nextIvlStr
assert ni(c, 2) == "2 days"
assert ni(c, 3) == "3 days"
assert ni(c, 4) == "4 days"
# if hard factor is <= 1, then hard may not increase
conf = d.decks.confForDid(1)
conf['rev']['hardFactor'] = 1
assert ni(c, 2) == "1 day"
def test_overdue_lapse():
# disabled in commit 3069729776990980f34c25be66410e947e9d51a2
return
d = getEmptyCol()
# add a note
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
# simulate a review that was lapsed and is now due for its normal review
c = f.cards()[0]
c.type = 2
c.queue = 1
c.due = -1
c.odue = -1
c.factor = STARTING_FACTOR
c.left = 2002
c.ivl = 0
c.flush()
d.sched._clearOverdue = False
# checkpoint
d.save()
d.sched.reset()
assert d.sched.counts() == (0, 2, 0)
c = d.sched.getCard()
d.sched.answerCard(c, 3)
# it should be due tomorrow
assert c.due == d.sched.today + 1
# revert to before
d.rollback()
d.sched._clearOverdue = True
# with the default settings, the overdue card should be removed from the
# learning queue
d.sched.reset()
assert d.sched.counts() == (0, 0, 1)
def test_finished():
d = getEmptyCol()
# nothing due
assert "Congratulations" in d.sched.finishedMsg()
assert "limit" not in d.sched.finishedMsg()
f = d.newNote()
f['Front'] = "one"; f['Back'] = "two"
d.addNote(f)
# have a new card
assert "new cards available" in d.sched.finishedMsg()
# turn it into a review
d.reset()
c = f.cards()[0]
c.startTimer()
d.sched.answerCard(c, 3)
# nothing should be due tomorrow, as it's due in a week
assert "Congratulations" in d.sched.finishedMsg()
assert "limit" not in d.sched.finishedMsg()
def test_nextIvl():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"; f['Back'] = "two"
d.addNote(f)
d.reset()
conf = d.decks.confForDid(1)
conf['new']['delays'] = [0.5, 3, 10]
conf['lapse']['delays'] = [1, 5, 9]
c = d.sched.getCard()
# new cards
##################################################
ni = d.sched.nextIvl
assert ni(c, 1) == 30
assert ni(c, 2) == (30+180)//2
assert ni(c, 3) == 180
assert ni(c, 4) == 4*86400
d.sched.answerCard(c, 1)
# cards in learning
##################################################
assert ni(c, 1) == 30
assert ni(c, 2) == (30+180)//2
assert ni(c, 3) == 180
assert ni(c, 4) == 4*86400
d.sched.answerCard(c, 3)
assert ni(c, 1) == 30
assert ni(c, 2) == (180+600)//2
assert ni(c, 3) == 600
assert ni(c, 4) == 4*86400
d.sched.answerCard(c, 3)
# normal graduation is tomorrow
assert ni(c, 3) == 1*86400
assert ni(c, 4) == 4*86400
# lapsed cards
##################################################
c.type = 2
c.ivl = 100
c.factor = STARTING_FACTOR
assert ni(c, 1) == 60
assert ni(c, 3) == 100*86400
assert ni(c, 4) == 100*86400
# review cards
##################################################
c.queue = 2
c.ivl = 100
c.factor = STARTING_FACTOR
# failing it should put it at 60s
assert ni(c, 1) == 60
# or 1 day if relearn is false
d.sched._cardConf(c)['lapse']['delays']=[]
assert ni(c, 1) == 1*86400
# (* 100 1.2 86400)10368000.0
assert ni(c, 2) == 10368000
# (* 100 2.5 86400)21600000.0
assert ni(c, 3) == 21600000
# (* 100 2.5 1.3 86400)28080000.0
assert ni(c, 4) == 28080000
assert d.sched.nextIvlStr(c, 4) == "10.8 months"
def test_bury():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
c = f.cards()[0]
f = d.newNote()
f['Front'] = "two"
d.addNote(f)
c2 = f.cards()[0]
# burying
d.sched.buryCards([c.id], manual=True)
c.load()
assert c.queue == -3
d.sched.buryCards([c2.id], manual=False)
c2.load()
assert c2.queue == -2
d.reset()
assert not d.sched.getCard()
d.sched.unburyCardsForDeck(type="manual")
c.load(); assert c.queue == 0
c2.load(); assert c2.queue == -2
d.sched.unburyCardsForDeck(type="siblings")
c2.load(); assert c2.queue == 0
d.sched.buryCards([c.id, c2.id])
d.sched.unburyCardsForDeck(type="all")
d.reset()
assert d.sched.counts() == (2, 0, 0)
def test_suspend():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
c = f.cards()[0]
# suspending
d.reset()
assert d.sched.getCard()
d.sched.suspendCards([c.id])
d.reset()
assert not d.sched.getCard()
# unsuspending
d.sched.unsuspendCards([c.id])
d.reset()
assert d.sched.getCard()
# should cope with rev cards being relearnt
c.due = 0; c.ivl = 100; c.type = 2; c.queue = 2; c.flush()
d.reset()
c = d.sched.getCard()
d.sched.answerCard(c, 1)
assert c.due >= time.time()
due = c.due
assert c.queue == 1
assert c.type == 3
d.sched.suspendCards([c.id])
d.sched.unsuspendCards([c.id])
c.load()
assert c.queue == 1
assert c.type == 3
assert c.due == due
# should cope with cards in cram decks
c.due = 1
c.flush()
cram = d.decks.newDyn("tmp")
d.sched.rebuildDyn()
c.load()
assert c.due != 1
assert c.did != 1
d.sched.suspendCards([c.id])
c.load()
assert c.due != 1
assert c.did != 1
assert c.odue == 1
def test_filt_reviewing_early_normal():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
c = f.cards()[0]
c.ivl = 100
c.type = c.queue = 2
# due in 25 days, so it's been waiting 75 days
c.due = d.sched.today + 25
c.mod = 1
c.factor = STARTING_FACTOR
c.startTimer()
c.flush()
d.reset()
assert d.sched.counts() == (0,0,0)
# create a dynamic deck and refresh it
did = d.decks.newDyn("Cram")
d.sched.rebuildDyn(did)
d.reset()
# should appear as normal in the deck list
assert sorted(d.sched.deckDueList())[0][2] == 1
# and should appear in the counts
assert d.sched.counts() == (0,0,1)
# grab it and check estimates
c = d.sched.getCard()
assert d.sched.answerButtons(c) == 4
assert d.sched.nextIvl(c, 1) == 600
assert d.sched.nextIvl(c, 2) == int(75*1.2)*86400
assert d.sched.nextIvl(c, 3) == int(75*2.5)*86400
assert d.sched.nextIvl(c, 4) == int(75*2.5*1.15)*86400
# answer 'good'
d.sched.answerCard(c, 3)
checkRevIvl(d, c, 90)
assert c.due == d.sched.today + c.ivl
assert not c.odue
# should not be in learning
assert c.queue == 2
# should be logged as a cram rep
assert d.db.scalar(
"select type from revlog order by id desc limit 1") == 3
# due in 75 days, so it's been waiting 25 days
c.ivl = 100
c.due = d.sched.today + 75
c.flush()
d.sched.rebuildDyn(did)
d.reset()
c = d.sched.getCard()
assert d.sched.nextIvl(c, 2) == 60*86400
assert d.sched.nextIvl(c, 3) == 100*86400
assert d.sched.nextIvl(c, 4) == 114*86400
def test_filt_keep_lrn_state():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
# fail the card outside filtered deck
c = d.sched.getCard()
d.sched.answerCard(c, 1)
assert c.type == c.queue == 1
# create a dynamic deck and refresh it
did = d.decks.newDyn("Cram")
d.sched.rebuildDyn(did)
d.reset()
# card should still be in learning state
c.load()
assert c.type == c.queue == 1
# emptying the deck preserves learning state
d.sched.emptyDyn(did)
c.load()
assert c.type == c.queue == 1
def test_preview():
# add cards
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
c = f.cards()[0]
orig = copy.copy(c)
f2 = d.newNote()
f2['Front'] = "two"
d.addNote(f2)
# cram deck
did = d.decks.newDyn("Cram")
cram = d.decks.get(did)
cram['resched'] = False
d.sched.rebuildDyn(did)
d.reset()
# grab the first card
c = d.sched.getCard()
assert d.sched.answerButtons(c) == 2
assert d.sched.nextIvl(c, 1) == 600
assert d.sched.nextIvl(c, 2) == 0
# failing it will push its due time back
due = c.due
d.sched.answerCard(c, 1)
assert c.due != due
# the other card should come next
c2 = d.sched.getCard()
assert c2.id != c.id
# passing it will remove it
d.sched.answerCard(c2, 2)
assert c2.queue == 0
assert c2.reps == 0
assert c2.type == 0
# the other card should appear again
c = d.sched.getCard()
assert c.id == orig.id
# emptying the filtered deck should restore card
d.sched.emptyDyn(did)
c.load()
assert c.queue == 0
assert c.reps == 0
assert c.type == 0
def test_ordcycle():
d = getEmptyCol()
# add two more templates and set second active
m = d.models.current(); mm = d.models
t = mm.newTemplate("Reverse")
t['qfmt'] = "{{Back}}"
t['afmt'] = "{{Front}}"
mm.addTemplate(m, t)
t = mm.newTemplate("f2")
t['qfmt'] = "{{Front}}"
t['afmt'] = "{{Back}}"
mm.addTemplate(m, t)
mm.save(m)
# create a new note; it should have 3 cards
f = d.newNote()
f['Front'] = "1"; f['Back'] = "1"
d.addNote(f)
assert d.cardCount() == 3
d.reset()
# ordinals should arrive in order
assert d.sched.getCard().ord == 0
assert d.sched.getCard().ord == 1
assert d.sched.getCard().ord == 2
def test_counts_idx():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"; f['Back'] = "two"
d.addNote(f)
d.reset()
assert d.sched.counts() == (1, 0, 0)
c = d.sched.getCard()
# counter's been decremented but idx indicates 1
assert d.sched.counts() == (0, 0, 0)
assert d.sched.countIdx(c) == 0
# answer to move to learn queue
d.sched.answerCard(c, 1)
assert d.sched.counts() == (0, 1, 0)
# fetching again will decrement the count
c = d.sched.getCard()
assert d.sched.counts() == (0, 0, 0)
assert d.sched.countIdx(c) == 1
# answering should add it back again
d.sched.answerCard(c, 1)
assert d.sched.counts() == (0, 1, 0)
def test_repCounts():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
d.reset()
# lrnReps should be accurate on pass/fail
assert d.sched.counts() == (1, 0, 0)
d.sched.answerCard(d.sched.getCard(), 1)
assert d.sched.counts() == (0, 1, 0)
d.sched.answerCard(d.sched.getCard(), 1)
assert d.sched.counts() == (0, 1, 0)
d.sched.answerCard(d.sched.getCard(), 3)
assert d.sched.counts() == (0, 1, 0)
d.sched.answerCard(d.sched.getCard(), 1)
assert d.sched.counts() == (0, 1, 0)
d.sched.answerCard(d.sched.getCard(), 3)
assert d.sched.counts() == (0, 1, 0)
d.sched.answerCard(d.sched.getCard(), 3)
assert d.sched.counts() == (0, 0, 0)
f = d.newNote()
f['Front'] = "two"
d.addNote(f)
d.reset()
# initial pass should be correct too
d.sched.answerCard(d.sched.getCard(), 3)
assert d.sched.counts() == (0, 1, 0)
d.sched.answerCard(d.sched.getCard(), 1)
assert d.sched.counts() == (0, 1, 0)
d.sched.answerCard(d.sched.getCard(), 4)
assert d.sched.counts() == (0, 0, 0)
# immediate graduate should work
f = d.newNote()
f['Front'] = "three"
d.addNote(f)
d.reset()
d.sched.answerCard(d.sched.getCard(), 4)
assert d.sched.counts() == (0, 0, 0)
# and failing a review should too
f = d.newNote()
f['Front'] = "three"
d.addNote(f)
c = f.cards()[0]
c.type = 2
c.queue = 2
c.due = d.sched.today
c.flush()
d.reset()
assert d.sched.counts() == (0, 0, 1)
d.sched.answerCard(d.sched.getCard(), 1)
assert d.sched.counts() == (0, 1, 0)
def test_timing():
d = getEmptyCol()
# add a few review cards, due today
for i in range(5):
f = d.newNote()
f['Front'] = "num"+str(i)
d.addNote(f)
c = f.cards()[0]
c.type = 2
c.queue = 2
c.due = 0
c.flush()
# fail the first one
d.reset()
c = d.sched.getCard()
d.sched.answerCard(c, 1)
# the next card should be another review
c2 = d.sched.getCard()
assert c2.queue == 2
# if the failed card becomes due, it should show first
c.due = time.time() - 1
c.flush()
d.reset()
c = d.sched.getCard()
assert c.queue == 1
def test_collapse():
d = getEmptyCol()
# add a note
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
d.reset()
# test collapsing
c = d.sched.getCard()
d.sched.answerCard(c, 1)
c = d.sched.getCard()
d.sched.answerCard(c, 4)
assert not d.sched.getCard()
def test_deckDue():
d = getEmptyCol()
# add a note with default deck
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
# and one that's a child
f = d.newNote()
f['Front'] = "two"
default1 = f.model()['did'] = d.decks.id("Default::1")
d.addNote(f)
# make it a review card
c = f.cards()[0]
c.queue = 2
c.due = 0
c.flush()
# add one more with a new deck
f = d.newNote()
f['Front'] = "two"
foobar = f.model()['did'] = d.decks.id("foo::bar")
d.addNote(f)
# and one that's a sibling
f = d.newNote()
f['Front'] = "three"
foobaz = f.model()['did'] = d.decks.id("foo::baz")
d.addNote(f)
d.reset()
assert len(d.decks.decks) == 5
cnts = d.sched.deckDueList()
assert cnts[0] == ["Default", 1, 1, 0, 1]
assert cnts[1] == ["Default::1", default1, 1, 0, 0]
assert cnts[2] == ["foo", d.decks.id("foo"), 0, 0, 0]
assert cnts[3] == ["foo::bar", foobar, 0, 0, 1]
assert cnts[4] == ["foo::baz", foobaz, 0, 0, 1]
tree = d.sched.deckDueTree()
assert tree[0][0] == "Default"
# sum of child and parent
assert tree[0][1] == 1
assert tree[0][2] == 1
assert tree[0][4] == 1
# child count is just review
assert tree[0][5][0][0] == "1"
assert tree[0][5][0][1] == default1
assert tree[0][5][0][2] == 1
assert tree[0][5][0][4] == 0
# code should not fail if a card has an invalid deck
c.did = 12345; c.flush()
d.sched.deckDueList()
d.sched.deckDueTree()
def test_deckTree():
d = getEmptyCol()
d.decks.id("new::b::c")
d.decks.id("new2")
# new should not appear twice in tree
names = [x[0] for x in d.sched.deckDueTree()]
names.remove("new")
assert "new" not in names
def test_deckFlow():
d = getEmptyCol()
# add a note with default deck
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
# and one that's a child
f = d.newNote()
f['Front'] = "two"
default1 = f.model()['did'] = d.decks.id("Default::2")
d.addNote(f)
# and another that's higher up
f = d.newNote()
f['Front'] = "three"
default1 = f.model()['did'] = d.decks.id("Default::1")
d.addNote(f)
# should get top level one first, then ::1, then ::2
d.reset()
assert d.sched.counts() == (3,0,0)
for i in "one", "three", "two":
c = d.sched.getCard()
assert c.note()['Front'] == i
d.sched.answerCard(c, 3)
def test_reorder():
d = getEmptyCol()
# add a note with default deck
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
f2 = d.newNote()
f2['Front'] = "two"
d.addNote(f2)
assert f2.cards()[0].due == 2
found=False
# 50/50 chance of being reordered
for i in range(20):
d.sched.randomizeCards(1)
if f.cards()[0].due != f.id:
found=True
break
assert found
d.sched.orderCards(1)
assert f.cards()[0].due == 1
# shifting
f3 = d.newNote()
f3['Front'] = "three"
d.addNote(f3)
f4 = d.newNote()
f4['Front'] = "four"
d.addNote(f4)
assert f.cards()[0].due == 1
assert f2.cards()[0].due == 2
assert f3.cards()[0].due == 3
assert f4.cards()[0].due == 4
d.sched.sortCards([
f3.cards()[0].id, f4.cards()[0].id], start=1, shift=True)
assert f.cards()[0].due == 3
assert f2.cards()[0].due == 4
assert f3.cards()[0].due == 1
assert f4.cards()[0].due == 2
def test_forget():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
c = f.cards()[0]
c.queue = 2; c.type = 2; c.ivl = 100; c.due = 0
c.flush()
d.reset()
assert d.sched.counts() == (0, 0, 1)
d.sched.forgetCards([c.id])
d.reset()
assert d.sched.counts() == (1, 0, 0)
def test_resched():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
c = f.cards()[0]
d.sched.reschedCards([c.id], 0, 0)
c.load()
assert c.due == d.sched.today
assert c.ivl == 1
assert c.queue == c.type == 2
d.sched.reschedCards([c.id], 1, 1)
c.load()
assert c.due == d.sched.today+1
assert c.ivl == +1
def test_norelearn():
d = getEmptyCol()
# add a note
f = d.newNote()
f['Front'] = "one"
d.addNote(f)
c = f.cards()[0]
c.type = 2
c.queue = 2
c.due = 0
c.factor = STARTING_FACTOR
c.reps = 3
c.lapses = 1
c.ivl = 100
c.startTimer()
c.flush()
d.reset()
d.sched.answerCard(c, 1)
d.sched._cardConf(c)['lapse']['delays'] = []
d.sched.answerCard(c, 1)
def test_failmult():
d = getEmptyCol()
f = d.newNote()
f['Front'] = "one"; f['Back'] = "two"
d.addNote(f)
c = f.cards()[0]
c.type = 2
c.queue = 2
c.ivl = 100
c.due = d.sched.today - c.ivl
c.factor = STARTING_FACTOR
c.reps = 3
c.lapses = 1
c.startTimer()
c.flush()
d.sched._cardConf(c)['lapse']['mult'] = 0.5
c = d.sched.getCard()
d.sched.answerCard(c, 1)
assert c.ivl == 50
d.sched.answerCard(c, 1)
assert c.ivl == 25
def test_moveVersions():
col = _getEmptyCol(schedVer=1)
n = col.newNote()
n['Front'] = "one"
col.addNote(n)
# make it a learning card
col.reset()
c = col.sched.getCard()
col.sched.answerCard(c, 1)
# the move to v2 should reset it to new
col.changeSchedulerVer(2)
c.load()
assert c.queue == 0
assert c.type == 0
# fail it again, and manually bury it
col.reset()
c = col.sched.getCard()
col.sched.answerCard(c, 1)
col.sched.buryCards([c.id])
c.load()
assert c.queue == -3
# revert to version 1
col.changeSchedulerVer(1)
# card should have moved queues
c.load()
assert c.queue == -2
# and it should be new again when unburied
col.sched.unburyCards()
c.load()
assert c.queue == c.type == 0