diff --git a/Vorlesungen/RK/KlausurLV_WS1415_Maerz2015.tex b/Vorlesungen/RK/KlausurLV_WS1415_Maerz2015.tex
index bb269e8..e0952e3 100644
--- a/Vorlesungen/RK/KlausurLV_WS1415_Maerz2015.tex
+++ b/Vorlesungen/RK/KlausurLV_WS1415_Maerz2015.tex
@@ -2,6 +2,9 @@
 \documentclass{article}
 \usepackage{amsmath}
 %\usepackage{epsf}
+%tkitz stuff
+\usepackage{tikz}
+\usepackage{listings}
 \DeclareMathSizes{10}{10}{10}{10}
 \setlength{\parindent}{0pt}
 \title{Klausur M\"arz 2015}
@@ -37,10 +40,178 @@
 			\textbf{a)}\\
 				- selbsttaktend: Empfänger kann Sendertakt aus Signal gewinnen \\
 				- gleichstromfrei: kein Gleichanteil im elektrischen Signal \\
-			\textbf{b)}\\
-				%Postscript include
-				%\epsfxsize=10pt
-				%\includegraphics[scale=1]{/postscripts/test.eps}
-				
-				
-\end{document}
\ No newline at end of file
+			\textbf{b)}\\\\
+				\begin{tikzpicture}[xscale=2]
+					\draw 	(0,0) -- (0.25,0) -- (0.25,0.5) -- (0.75,0.5) -- (0.75,0) -- (1,0) --
+							(1,0.5) -- (1.25,0.5) -- (1.25,0) -- (1.5,0) -- (1.5,0.5) -- (1.75,0.5) --
+							(1.75,0) -- (2.25,0) -- (2.25,0.5) -- (2.5,0.5) -- (2.5,0) -- (2.75,0) -- 
+							(2.75,0.5) -- (3.25,0.5) -- (3.25,0) -- (3.5,0) -- (3.5,0.5) -- (3.75,0.5) -- 
+							(3.75,0) -- (4,0);
+				\end{tikzpicture}\\
+				-\hspace{3mm}0\hspace{8mm}1\hspace{8.5mm}1\hspace{8mm}1\hspace{9mm}0\hspace{8mm}
+				0\hspace{8mm}1\hspace{8mm}1 \;\;- \\
+		\section{TCP}
+		\subsection{Round-Trip-Time}
+			\[ RTT = 2*d_{prop} + 10ms = 2*45ms+10ms = 100ms \]			
+		\subsection{TCP Verlauf}
+			$A->B: SYN, Seq=1, Ack=XX 									\\
+			A<-B: SYN, ACK, Seq=XX+1, Ack=2 							\\
+			A->B: ACK, Seq=2, Ack=XX+2 									\\
+			\textbf{\textit{Verbindung erfolgreich aufgebaut}} 			\\
+			A<-B: Data, Seq=XX+2, Ack=3 \hspace*{1cm}|\;\;CW = 1		\\
+			A->B: ACK, Seq=3, Ack=XX+3									\\
+			\textbf{\textit{BANG!}}										\\
+			A<-B: Data, Seq=XX+3, Ack=4									\\
+			A<-B: Data, Seq=XX+4, Ack=5 \hspace*{1cm}|\;\; CW = 2		\\
+			\textbf{\textit{Demnach weiterer Verlauf nach tau:}}		\\
+			A<-B: Data, Seq=XX+3, Ack=4 \hspace*{1cm}|\;\; CW = 1		\\
+			A->B: ACK, Seq=4, Ack=XX+4									\\
+			A<-B: Data, Seq=XX+4, Ack=5 \hspace*{1cm}|\;\; CW = 2		\\
+			A<-B: Data, Seq=XX+5, Ack=6									\\
+			A->B: ACK, Seq=5, Ack=XX+5									\\
+			A->B: ACK, Seq=6, Ack=XX+6									\\
+			$\\
+			Nach dem 4. Paket wurden 5000 Bytes uebertragen.
+		\subsection{Leistungsanalyse}
+				$d_{prop} = 45ms$\\\\
+				$d_{trans} = \frac{L}{R} = 1ms\;\;denn\;10\frac{MBit}{s} =
+				10^6 \frac{Bit}{s} = 1250\frac{Byte}{s}$\\\\
+				$\frac{O}{L} = \frac{5000}{1250} = 4$\;\;\;\;$t = 2RTT + 4*1ms + 4*45ms = 384 (mit\;RTT\;als\;100ms)$
+		\newpage
+		\section{Programieraufgabe TCP-FIN}
+			\begin{lstlisting}[language=java]
+public class TCPFIN extends base {
+	final int FIN_WAIT_1 = 1;
+	final int FIN_WAIT_2 = 2;
+	final int CLOSING = 3;
+	final int TIME_WAIT = 4;
+	final int CLOSED = 5;
+
+	int state;
+
+	void close() throws IOException {
+		state = FIN_WAIT_1;
+		send(FIN);
+	}
+
+	void receive(int flag) throws IOException {
+		if (flag == FIN) {
+			if (state == FIN_WAIT_1) {
+				state = CLOSING;
+			} else if (state == FIN_WAIT_2) {
+				state = TIME_WAIT;
+				startTimer();
+			}
+			send(ACK);
+		} else if (flag == ACK) {
+			if (state == FIN_WAIT_1) {
+				state = FIN_WAIT_2;
+			} else if (state == CLOSING) {
+				state = TIME_WAIT;
+				startTimer();
+			}
+		}
+	}
+
+	void timeout() throws WrongStateException {
+		if (state != TIME_WAIT) {
+			throw new WrongStateException();
+		}
+		state = CLOSED;
+	}
+}
+\end{lstlisting}
+\newpage
+%unformated codeblock end
+	\section{Routingverfahren}
+		\subsection{Routingverfahren}
+			\subsubsection{Darstellung}
+				\begin{tikzpicture}
+					%Knoten
+					\draw(0,2) circle [radius=0.3];
+					\draw(3,2) circle [radius=0.3];
+					\draw(6,2) circle [radius=0.3];
+					\draw(0,0) circle [radius=0.3];
+					\draw(3,0) circle [radius=0.3];
+					%Beschriftung Knoten
+					\node[purple] at (0,2) {P};
+					\node[purple] at (3,2) {A};
+					\node[purple] at (6,2) {S};
+					\node[purple] at (0,0) {C};
+					\node[purple] at (3,0) {B};
+					%Linien
+					\draw (0.3,0) -- (2.7,0);
+					\draw (0,0.3) -- (0,1.7);
+					\draw (0.3,2) -- (2.7,2);
+					\draw (3,0.3) -- (3,1.7);
+					\draw (3.3,2) -- (5.7,2);
+					\draw (3.3,0) -- (6,1.7);
+					\draw (3,0.3) -- (0,1.7);
+					%Beschriftungen Linien
+					\node [left,red] at (0,1) {1};
+					\node [above,red] at (1.5,2) {8};
+					\node [above,red] at (1.5,1) {4};
+					\node [below,red] at (1.5,0) {2};
+					\node [left,red] at (3,1) {2};
+					\node [red] at (4.5,1) {4};
+					\node [above,red] at (4.5,2) {1};
+				\end{tikzpicture}
+			\subsubsection{Minimal aufspannender Baum}
+				\begin{tabular}{| l | c | c | c | c | c |}
+					\hline
+					S	&	N'	&	D(A),p(A)	&	D(B),p(B)	&	D(C),p(C)	&	D(P),p(P) 	\\ \hline
+					test&test	&test			&test			&test			&test			\\ \hline
+				\end{tabular}
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+\end{document}